4x+2y+3z^2-12=0

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Solution for 4x+2y+3z^2-12=0 equation:


Simplifying
4x + 2y + 3z2 + -12 = 0

Reorder the terms:
-12 + 4x + 2y + 3z2 = 0

Solving
-12 + 4x + 2y + 3z2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '12' to each side of the equation.
-12 + 4x + 2y + 12 + 3z2 = 0 + 12

Reorder the terms:
-12 + 12 + 4x + 2y + 3z2 = 0 + 12

Combine like terms: -12 + 12 = 0
0 + 4x + 2y + 3z2 = 0 + 12
4x + 2y + 3z2 = 0 + 12

Combine like terms: 0 + 12 = 12
4x + 2y + 3z2 = 12

Add '-2y' to each side of the equation.
4x + 2y + -2y + 3z2 = 12 + -2y

Combine like terms: 2y + -2y = 0
4x + 0 + 3z2 = 12 + -2y
4x + 3z2 = 12 + -2y

Add '-3z2' to each side of the equation.
4x + 3z2 + -3z2 = 12 + -2y + -3z2

Combine like terms: 3z2 + -3z2 = 0
4x + 0 = 12 + -2y + -3z2
4x = 12 + -2y + -3z2

Divide each side by '4'.
x = 3 + -0.5y + -0.75z2

Simplifying
x = 3 + -0.5y + -0.75z2

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